Skip to main content

[Community Question] Geometry: Projection of tilted triangle onto a wall

One of our user asked:

A 3,4,5 triangle resting on its side of length 3 is tilted so that it makes a 60 degree angle with the floor and rests on the wall. What are the dimensions of the projection of the triangle onto the wall. The height is $2\sqrt{3}$ I can't seem to figure out how to find the length of the base. The answer given is $\frac{3}{4}2\sqrt{3}$. I'd appreciate any explanations in deriving this. Thank you.


Comments

Popular posts from this blog

[Community Question] Linear-algebra: non-negative matrix satisfying two conditions

One of our user asked: A real matrix $B$ is called non-negative if every entry is non-negative. We will denote this by $B\ge 0$ . I want to find a non-negative matrix $B$ satisfying the following two conditions: (1) $(I-B)^{-1}$ exists but not non-negative. Here $I$ is the identity matrix. (2) There is a non-zero and non-negative vector $\vec{d}$ such that $(I-B)^{-1}\vec{d}\ge 0$ . I tried all the $2\times 2$ matrices, but it did not work. I conjecture that such a $B$ does not exist, but don't know how to prove it.

[Community Question] Linear-algebra: Are linear transformations between infinite dimensional vector spaces always differentiable?

One of our user asked: In class we saw that every linear transformation is differentiable (since there's always a linear approximation for them) and we also saw that a differentiable function must be continuous, so it must be true that all linear operators are continuous, however, I just read that between infinite dimensional vector spaces this is not necessarily true. I would like to know where's the flaw in my reasoning (I suspect that linear transformations between infinite dimensional vector spaces are not always differentiable).