One of our user asked:
The following set : $$\{(x,y) \in \mathbb{R}^2 \mid x+y \leq 1, x\geq 0, y \geq 0 \}$$ is a triangle. One way to see it is simply that we draw all points under the line of equation $y = 1-x$ with positive coordinates.
My question is :
-
Is it possible with inequalities (just as the one that describe a triangle) to draw some other nice shapes like parallelogram or more generally regular polygons ?
-
Moreover I suspect that there is some linear algebra behind these inequalities. So maybe for example linear algebra can help proving that the above inequality makes a triangle.
Thank you !
Comments
Post a Comment