One of our user asked:
Let, the point $K$ is the center of inscribed circle of a triangle. The circle touching the edges of the triangle is mentioned.
$\angle ABC=90°$
$AE=4$ and $CF=12$
Find the radius of inscribed circle of the triangle:
A)3
B)4
C)5
D)6
E)7
My attempts:
The radius of inscribed circle, we have,
$r=\frac{a+b-c}{2}$, where, $c=\sqrt{a^2+b^2}$. Then, I need $AB$ and $BC$. Or, I must know what are $BE$ and $BF$. I 'm stuck.
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